### Lesson 13: Turtle and lots of ifs

posted Feb 6, 2020, 8:05 AM by Attila Lengyel
 import turtle as tjohn = t.Turtle()john.shape("turtle")john.fillcolor("blue")john.pencolor("blue")screen = t.Screen()john.penup()john.setposition(-200,200)john.pendown()for x in range(4): john.fd(400) john.right(90)john.penup()john.setposition(0,0)def define_action(john): if john.xcor() < 200 and john.ypos()> 200: return 1 if john.xcor() > 200 and john.ypos()> 200: return 3 if john.xcor() > 200 and john.ypos() < -200: return 5 if john.xcor() < -200 and john.ypos()<-200: return 7 if john.ycor() > 200: return 2 if john.xcor() > 200: return 4 if john.ycor() < -200: return 6 if john.xcor() < -200: return 8 return 9def action(john): item = define_action() john.write(item, font=("Arial", 64, "normal")) if item == 1: john.setposition(-199,199) if item == 3: john.setposition(199,199) if item == 5: john.setposition(199,-199) if item == 7: john.setposition(-199,-199) if item == 2: john.setposition(john.xcor(), 199) if item == 4: john.setposition(199, john.ycor()) if item == 6: john.setposition(john.xcor(),-199) if item == 8: john.setposition(-199, john.ycor()) def move_forward(): john.pencolor("blue") john.forward(10)def move_backward(): john.pencolor("white") john.backward(10)def turn_right(): john.right(10)def turn_left(): john.left(10)def clear_screen(): john.clear()def start_draw(): john.pendown()def stop_draw(): john.penup()screen.onkey(move_forward, "Up")screen.onkey(move_backward, "Down")screen.onkey(turn_right, "Right")screen.onkey(turn_left, "Left")screen.onkey(clear_screen, "c")screen.onkey(stop_draw, "u")screen.onkey(start_draw, "d")screen.listen()